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Incorporate Move Semantics exercises from Felix's tutorial
👍 👍 👍 Connects to #6
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// Make me compile! Scroll down for hints :)
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pub fn main() {
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let vec0 = Vec::new();
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let vec1 = fill_vec(vec0);
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println!("{} has length {} content `{:?}`", "vec1", vec1.len(), vec1);
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vec1.push(88);
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println!("{} has length {} content `{:?}`", "vec1", vec1.len(), vec1);
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}
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fn fill_vec(vec: Vec<i32>) -> Vec<i32> {
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let mut vec = vec;
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vec.push(22);
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vec.push(44);
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vec.push(66);
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vec
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}
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// So you've got the "cannot borrow immutable local variable `vec1` as mutable" error on line 8,
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// right? The fix for this is going to be adding one keyword, and the addition is NOT on line 8
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// where the error is.
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// Make me compile without changing line 9! Scroll down for hints :)
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pub fn main() {
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let vec0 = Vec::new();
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let mut vec1 = fill_vec(vec0);
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// Do not change the following line!
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println!("{} has length {} content `{:?}`", "vec0", vec0.len(), vec0);
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vec1.push(88);
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println!("{} has length {} content `{:?}`", "vec1", vec1.len(), vec1);
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}
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fn fill_vec(vec: Vec<i32>) -> Vec<i32> {
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let mut vec = vec;
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vec.push(22);
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vec.push(44);
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vec.push(66);
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vec
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}
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// So `vec0` is being *moved* into the function `fill_vec` when we call it on
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// line 6, which means it gets dropped at the end of `fill_vec`, which means we
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// can't use `vec0` again on line 9 (or anywhere else in `main` after the
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// `fill_vec` call for that matter). We could fix this in a few ways, try them
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// all!
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// 1. Make another, separate version of the data that's in `vec0` and pass that
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// to `fill_vec` instead.
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// 2. Make `fill_vec` borrow its argument instead of taking ownership of it,
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// and then copy the data within the function in order to return an owned
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// `Vec<i32>`
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// 3. Make `fill_vec` *mutably* borrow its argument (which will need to be
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// mutable), modify it directly, then not return anything. Then you can get rid
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// of `vec1` entirely -- note that this will change what gets printed by the
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// first `println!`
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// Make me compile without adding new lines-- just changing existing lines!
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// (no lines with multiple semicolons necessary!)
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// Scroll down for hints :)
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pub fn main() {
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let vec0 = Vec::new();
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let mut vec1 = fill_vec(vec0);
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println!("{} has length {} content `{:?}`", "vec1", vec1.len(), vec1);
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vec1.push(88);
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println!("{} has length {} content `{:?}`", "vec1", vec1.len(), vec1);
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}
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fn fill_vec(vec: Vec<i32>) -> Vec<i32> {
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vec.push(22);
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vec.push(44);
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vec.push(66);
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vec
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}
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// The difference between this one and the previous ones is that the first line
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// of `fn fill_vec` that had `let mut vec = vec;` is no longer there. You can,
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// instead of adding that line back, add `mut` in one place that will change
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// an existing binding to be a mutable binding instead of an immutable one :)
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// Refactor this code so that instead of having `vec0` and creating the vector
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// in `fn main`, we instead create it within `fn fill_vec` and transfer the
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// freshly created vector from fill_vec to its caller. Scroll for hints!
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pub fn main() {
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let vec0 = Vec::new();
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let mut vec1 = fill_vec(vec0);
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println!("{} has length {} content `{:?}`", "vec1", vec1.len(), vec1);
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vec1.push(88);
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println!("{} has length {} content `{:?}`", "vec1", vec1.len(), vec1);
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}
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fn fill_vec(vec: Vec<i32>) -> Vec<i32> {
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let mut vec = vec;
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vec.push(22);
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vec.push(44);
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vec.push(66);
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vec
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}
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// Stop reading whenever you feel like you have enough direction :) Or try
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// doing one step and then fixing the compiler errors that result!
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// So the end goal is to:
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// - get rid of the first line in main that creates the new vector
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// - so then `vec0` doesn't exist, so we can't pass it to `fill_vec`
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// - we don't want to pass anything to `fill_vec`, so its signature should
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// reflect that it does not take any arguments
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// - since we're not creating a new vec in `main` anymore, we need to create
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// a new vec in `fill_vec`, similarly to the way we did in `main`
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