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generics1 rewrite and solution
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@ -1,7 +1,18 @@
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// This shopping list program isn't compiling! Use your knowledge of generics to
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// fix it.
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// `Vec<T>` is generic over the type `T`. In most cases, the compiler is able to
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// infer `T`, for example after pushing a value with a concrete type to the vector.
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// But in this exercise, the compiler needs some help through a type annotation.
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fn main() {
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let mut shopping_list: Vec<?> = Vec::new();
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shopping_list.push("milk");
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// TODO: Fix the compiler error by annotating the type of the vector
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// `Vec<T>`. Choose `T` as some integer type that can be created from
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// `u8` and `i8`.
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let mut numbers = Vec::new();
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// Don't change the lines below.
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let n1: u8 = 42;
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numbers.push(n1.into());
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let n2: i8 = -1;
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numbers.push(n2.into());
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println!("{numbers:?}");
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}
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@ -734,8 +734,13 @@ test = false
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hint = """
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Vectors in Rust make use of generics to create dynamically sized arrays of any
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type.
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If the vector `numbers` has the type `Vec<T>`, then we can only push values of
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type `T` to it. By using `into()` before pushing, we ask the compiler to convert
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`n1` and `n2` to `T`. But the compiler doesn't know what `T` is yet and needs a
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type annotation.
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You need to tell the compiler what type we are pushing onto this vector."""
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`u8` and `i8` can both be converted to `i16`, `i32` and `i64`. Choose one for
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the generic of the vector."""
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[[exercises]]
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name = "generics2"
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@ -1 +1,17 @@
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// Solutions will be available before the stable release. Thank you for testing the beta version 🥰
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// `Vec<T>` is generic over the type `T`. In most cases, the compiler is able to
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// infer `T`, for example after pushing a value with a concrete type to the vector.
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// But in this exercise, the compiler needs some help through a type annotation.
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fn main() {
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// `u8` and `i8` can both be converted to `i16`.
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let mut numbers: Vec<i16> = Vec::new();
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// ^^^^^^^^^^ added
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// Don't change the lines below.
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let n1: u8 = 42;
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numbers.push(n1.into());
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let n2: i8 = -1;
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numbers.push(n2.into());
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println!("{numbers:?}");
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}
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