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30d12d4c16
Instead of letting the compiler to figure out the optimal way to rotate register usage, explicitly rotate the register names with cpp. Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org> Signed-off-by: Junio C Hamano <gitster@pobox.com>
222 lines
5.7 KiB
C
222 lines
5.7 KiB
C
/*
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* Based on the Mozilla SHA1 (see mozilla-sha1/sha1.c),
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* optimized to do word accesses rather than byte accesses,
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* and to avoid unnecessary copies into the context array.
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*/
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#include <string.h>
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#include <arpa/inet.h>
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#include "sha1.h"
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/* Hash one 64-byte block of data */
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static void blk_SHA1Block(blk_SHA_CTX *ctx, const unsigned int *data);
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void blk_SHA1_Init(blk_SHA_CTX *ctx)
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{
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ctx->size = 0;
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/* Initialize H with the magic constants (see FIPS180 for constants)
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*/
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ctx->H[0] = 0x67452301;
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ctx->H[1] = 0xefcdab89;
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ctx->H[2] = 0x98badcfe;
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ctx->H[3] = 0x10325476;
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ctx->H[4] = 0xc3d2e1f0;
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}
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void blk_SHA1_Update(blk_SHA_CTX *ctx, const void *data, unsigned long len)
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{
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int lenW = ctx->size & 63;
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ctx->size += len;
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/* Read the data into W and process blocks as they get full
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*/
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if (lenW) {
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int left = 64 - lenW;
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if (len < left)
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left = len;
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memcpy(lenW + (char *)ctx->W, data, left);
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lenW = (lenW + left) & 63;
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len -= left;
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data += left;
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if (lenW)
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return;
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blk_SHA1Block(ctx, ctx->W);
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}
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while (len >= 64) {
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blk_SHA1Block(ctx, data);
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data += 64;
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len -= 64;
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}
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if (len)
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memcpy(ctx->W, data, len);
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}
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void blk_SHA1_Final(unsigned char hashout[20], blk_SHA_CTX *ctx)
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{
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static const unsigned char pad[64] = { 0x80 };
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unsigned int padlen[2];
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int i;
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/* Pad with a binary 1 (ie 0x80), then zeroes, then length
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*/
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padlen[0] = htonl(ctx->size >> 29);
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padlen[1] = htonl(ctx->size << 3);
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i = ctx->size & 63;
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blk_SHA1_Update(ctx, pad, 1+ (63 & (55 - i)));
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blk_SHA1_Update(ctx, padlen, 8);
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/* Output hash
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*/
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for (i = 0; i < 5; i++)
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((unsigned int *)hashout)[i] = htonl(ctx->H[i]);
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}
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#if defined(__i386__) || defined(__x86_64__)
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#define SHA_ASM(op, x, n) ({ unsigned int __res; __asm__(op " %1,%0":"=r" (__res):"i" (n), "0" (x)); __res; })
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#define SHA_ROL(x,n) SHA_ASM("rol", x, n)
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#define SHA_ROR(x,n) SHA_ASM("ror", x, n)
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#else
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#define SHA_ROT(X,l,r) (((X) << (l)) | ((X) >> (r)))
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#define SHA_ROL(X,n) SHA_ROT(X,n,32-(n))
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#define SHA_ROR(X,n) SHA_ROT(X,32-(n),n)
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#endif
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/* This "rolls" over the 512-bit array */
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#define W(x) (array[(x)&15])
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/*
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* Where do we get the source from? The first 16 iterations get it from
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* the input data, the next mix it from the 512-bit array.
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*/
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#define SHA_SRC(t) htonl(data[t])
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#define SHA_MIX(t) SHA_ROL(W(t+13) ^ W(t+8) ^ W(t+2) ^ W(t), 1)
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#define SHA_ROUND(t, input, fn, constant, A, B, C, D, E) do { \
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unsigned int TEMP = input(t); W(t) = TEMP; \
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TEMP += E + SHA_ROL(A,5) + (fn) + (constant); \
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B = SHA_ROR(B, 2); E = TEMP; } while (0)
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#define T_0_15(t, A, B, C, D, E) SHA_ROUND(t, SHA_SRC, (((C^D)&B)^D) , 0x5a827999, A, B, C, D, E )
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#define T_16_19(t, A, B, C, D, E) SHA_ROUND(t, SHA_MIX, (((C^D)&B)^D) , 0x5a827999, A, B, C, D, E )
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#define T_20_39(t, A, B, C, D, E) SHA_ROUND(t, SHA_MIX, (B^C^D) , 0x6ed9eba1, A, B, C, D, E )
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#define T_40_59(t, A, B, C, D, E) SHA_ROUND(t, SHA_MIX, ((B&C)+(D&(B^C))) , 0x8f1bbcdc, A, B, C, D, E )
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#define T_60_79(t, A, B, C, D, E) SHA_ROUND(t, SHA_MIX, (B^C^D) , 0xca62c1d6, A, B, C, D, E )
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static void blk_SHA1Block(blk_SHA_CTX *ctx, const unsigned int *data)
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{
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unsigned int A,B,C,D,E;
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unsigned int array[16];
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A = ctx->H[0];
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B = ctx->H[1];
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C = ctx->H[2];
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D = ctx->H[3];
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E = ctx->H[4];
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/* Round 1 - iterations 0-16 take their input from 'data' */
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T_0_15( 0, A, B, C, D, E);
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T_0_15( 1, E, A, B, C, D);
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T_0_15( 2, D, E, A, B, C);
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T_0_15( 3, C, D, E, A, B);
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T_0_15( 4, B, C, D, E, A);
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T_0_15( 5, A, B, C, D, E);
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T_0_15( 6, E, A, B, C, D);
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T_0_15( 7, D, E, A, B, C);
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T_0_15( 8, C, D, E, A, B);
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T_0_15( 9, B, C, D, E, A);
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T_0_15(10, A, B, C, D, E);
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T_0_15(11, E, A, B, C, D);
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T_0_15(12, D, E, A, B, C);
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T_0_15(13, C, D, E, A, B);
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T_0_15(14, B, C, D, E, A);
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T_0_15(15, A, B, C, D, E);
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/* Round 1 - tail. Input from 512-bit mixing array */
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T_16_19(16, E, A, B, C, D);
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T_16_19(17, D, E, A, B, C);
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T_16_19(18, C, D, E, A, B);
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T_16_19(19, B, C, D, E, A);
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/* Round 2 */
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T_20_39(20, A, B, C, D, E);
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T_20_39(21, E, A, B, C, D);
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T_20_39(22, D, E, A, B, C);
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T_20_39(23, C, D, E, A, B);
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T_20_39(24, B, C, D, E, A);
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T_20_39(25, A, B, C, D, E);
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T_20_39(26, E, A, B, C, D);
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T_20_39(27, D, E, A, B, C);
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T_20_39(28, C, D, E, A, B);
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T_20_39(29, B, C, D, E, A);
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T_20_39(30, A, B, C, D, E);
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T_20_39(31, E, A, B, C, D);
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T_20_39(32, D, E, A, B, C);
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T_20_39(33, C, D, E, A, B);
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T_20_39(34, B, C, D, E, A);
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T_20_39(35, A, B, C, D, E);
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T_20_39(36, E, A, B, C, D);
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T_20_39(37, D, E, A, B, C);
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T_20_39(38, C, D, E, A, B);
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T_20_39(39, B, C, D, E, A);
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/* Round 3 */
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T_40_59(40, A, B, C, D, E);
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T_40_59(41, E, A, B, C, D);
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T_40_59(42, D, E, A, B, C);
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T_40_59(43, C, D, E, A, B);
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T_40_59(44, B, C, D, E, A);
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T_40_59(45, A, B, C, D, E);
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T_40_59(46, E, A, B, C, D);
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T_40_59(47, D, E, A, B, C);
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T_40_59(48, C, D, E, A, B);
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T_40_59(49, B, C, D, E, A);
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T_40_59(50, A, B, C, D, E);
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T_40_59(51, E, A, B, C, D);
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T_40_59(52, D, E, A, B, C);
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T_40_59(53, C, D, E, A, B);
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T_40_59(54, B, C, D, E, A);
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T_40_59(55, A, B, C, D, E);
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T_40_59(56, E, A, B, C, D);
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T_40_59(57, D, E, A, B, C);
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T_40_59(58, C, D, E, A, B);
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T_40_59(59, B, C, D, E, A);
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/* Round 4 */
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T_60_79(60, A, B, C, D, E);
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T_60_79(61, E, A, B, C, D);
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T_60_79(62, D, E, A, B, C);
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T_60_79(63, C, D, E, A, B);
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T_60_79(64, B, C, D, E, A);
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T_60_79(65, A, B, C, D, E);
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T_60_79(66, E, A, B, C, D);
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T_60_79(67, D, E, A, B, C);
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T_60_79(68, C, D, E, A, B);
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T_60_79(69, B, C, D, E, A);
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T_60_79(70, A, B, C, D, E);
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T_60_79(71, E, A, B, C, D);
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T_60_79(72, D, E, A, B, C);
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T_60_79(73, C, D, E, A, B);
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T_60_79(74, B, C, D, E, A);
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T_60_79(75, A, B, C, D, E);
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T_60_79(76, E, A, B, C, D);
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T_60_79(77, D, E, A, B, C);
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T_60_79(78, C, D, E, A, B);
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T_60_79(79, B, C, D, E, A);
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ctx->H[0] += A;
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ctx->H[1] += B;
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ctx->H[2] += C;
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ctx->H[3] += D;
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ctx->H[4] += E;
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}
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