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Don't ever return corrupt objects from "parse_object()" 

Looking at the SHA1 validation code due to the corruption that Alexander
Litvinov is seeing under Cygwin, I notice that one of the most central
places where we read objects, we actually do end up verifying the SHA1 of
the result, but then we happily parse it anyway.

And using "printf" to write the error message means that it not only can
get lost, but will actually mess up stdout, and cause other strange and
hard-to-debug failures downstream.

Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
Signed-off-by: Junio C Hamano <junkio@cox.net>
This commit is contained in:
Linus Torvalds 2007-03-20 10:05:20 -07:00 committed by Junio C Hamano
parent 9096c660a8
commit acdeec62cb
1 changed files with 4 additions and 2 deletions
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6
object.c
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@ -184,8 +184,10 @@ struct object *parse_object(const unsigned char *sha1)
if (buffer) {
struct object *obj;
if (check_sha1_signature(sha1, buffer, size, typename(type)) < 0)
printf("sha1 mismatch %s\n", sha1_to_hex(sha1));
if (check_sha1_signature(sha1, buffer, size, typename(type)) < 0) {
error("sha1 mismatch %s\n", sha1_to_hex(sha1));
return NULL;
}
obj = parse_object_buffer(sha1, type, size, buffer, &eaten);
if (!eaten)