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builtin_diff_tree(): make it obvious that function wants two entries 

Instead of accepting an array and using exactly two elements from the
array, take two single (struct object_array_entry *) arguments.

Signed-off-by: Michael Haggerty <mhagger@alum.mit.edu>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Michael Haggerty 2013-05-25 11:08:03 +02:00 committed by Junio C Hamano
parent df835d3a0c
commit 91de344d76
1 changed files with 10 additions and 9 deletions
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19
builtin/diff.c
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@ -153,7 +153,8 @@ static int builtin_diff_index(struct rev_info *revs,
static int builtin_diff_tree(struct rev_info *revs,
int argc, const char **argv,
struct object_array_entry *ent)
struct object_array_entry *ent0,
struct object_array_entry *ent1)
{
const unsigned char *(sha1[2]);
int swap = 0;
@ -161,13 +162,14 @@ static int builtin_diff_tree(struct rev_info *revs,
if (argc > 1)
usage(builtin_diff_usage);
/* We saw two trees, ent[0] and ent[1].
* if ent[1] is uninteresting, they are swapped
/*
* We saw two trees, ent0 and ent1. If ent1 is uninteresting,
* swap them.
*/
if (ent[1].item->flags & UNINTERESTING)
if (ent1->item->flags & UNINTERESTING)
swap = 1;
sha1[swap] = ent[0].item->sha1;
sha1[1-swap] = ent[1].item->sha1;
sha1[swap] = ent0->item->sha1;
sha1[1-swap] = ent1->item->sha1;
diff_tree_sha1(sha1[0], sha1[1], "", &revs->diffopt);
log_tree_diff_flush(revs);
return 0;
@ -403,7 +405,7 @@ int cmd_diff(int argc, const char **argv, const char *prefix)
else if (ents == 1)
result = builtin_diff_index(&rev, argc, argv);
else if (ents == 2)
result = builtin_diff_tree(&rev, argc, argv, ent);
result = builtin_diff_tree(&rev, argc, argv, &ent[0], &ent[1]);
else if (ent[0].item->flags & UNINTERESTING) {
/*
* diff A...B where there is at least one merge base
@ -412,8 +414,7 @@ int cmd_diff(int argc, const char **argv, const char *prefix)
* between the base and B. Note that we pick one
* merge base at random if there are more than one.
*/
ent[1] = ent[ents-1];
result = builtin_diff_tree(&rev, argc, argv, ent);
result = builtin_diff_tree(&rev, argc, argv, &ent[0], &ent[ents-1]);
} else
result = builtin_diff_combined(&rev, argc, argv,
ent, ents);