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get_tree_entry(): do not call find_tree_entry() on an empty tree

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We know we will find nothing.

This incidentally squelches false warning from gcc about potentially
uninitialized usage of t.entry fields. For an empty tree, it is true that
init_tree_desc() does not call decode_tree_entry() and the tree_desc is
left uninitialized, but find_tree_entry() only calls tree_entry_extract()
that uses the tree_desc while it has more things to read from the tree, so
the uninitialized t.entry fields are never used in such a case anyway.

Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Junio C Hamano 2011-10-27 11:18:40 -07:00
parent 0de1633783
commit 5fb8c05f2e
1 changed files with 7 additions and 3 deletions
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10
tree-walk.c
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@ -465,7 +465,6 @@ int get_tree_entry(const unsigned char *tree_sha1, const char *name, unsigned ch
int retval;
void *tree;
unsigned long size;
struct tree_desc t;
unsigned char root[20];
tree = read_object_with_reference(tree_sha1, tree_type, &size, root);
@ -478,8 +477,13 @@ int get_tree_entry(const unsigned char *tree_sha1, const char *name, unsigned ch
return 0;
}
init_tree_desc(&t, tree, size);
retval = find_tree_entry(&t, name, sha1, mode);
if (!size) {
retval = -1;
} else {
struct tree_desc t;
init_tree_desc(&t, tree, size);
retval = find_tree_entry(&t, name, sha1, mode);
}
free(tree);
return retval;
}