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style: do not "break" in switch() after "return"

Remove this unreachable code. It was found by SunCC, it's found by a
non-fatal warning emitted by SunCC. It's one of the things it's more
vehement about than GCC & Clang.

It complains about a lot of other similarly unreachable code, e.g. a
BUG(...) without a "return", and a "return 0" after a long if/else,
both of whom have "return" statements. Those are also genuine
redundancies to a compiler, but arguably make the code a bit easier to
read & less fragile to maintain.

These return/break cases are just unnecessary however, and as seen
here the surrounding code just did a plain "return" without a "break"
already.

Signed-off-by: Ævar Arnfjörð Bjarmason <avarab@gmail.com>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Ævar Arnfjörð Bjarmason 2020-12-16 00:50:27 +01:00 committed by Junio C Hamano
parent 898f80736c
commit 56f56ac50b
2 changed files with 0 additions and 3 deletions

View File

@ -3948,10 +3948,8 @@ static int check_patch(struct apply_state *state, struct patch *patch)
break; /* happy */
case EXISTS_IN_INDEX:
return error(_("%s: already exists in index"), new_name);
break;
case EXISTS_IN_INDEX_AS_ITA:
return error(_("%s: does not match index"), new_name);
break;
case EXISTS_IN_WORKTREE:
return error(_("%s: already exists in working directory"),
new_name);

View File

@ -923,7 +923,6 @@ static struct commit *get_commit(struct rev_cmdline_entry *e, char *full_name)
if (!tag)
die("Tag %s points nowhere?", e->name);
return (struct commit *)tag;
break;
}
default:
return NULL;