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strbuf_branchname: drop return value

The return value from strbuf_branchname() is confusing and
useless: it's 0 if the whole name was consumed by an @-mark,
but otherwise is the length of the original name we fed.

No callers actually look at the return value, so let's just
get rid of it.

Signed-off-by: Jeff King <peff@peff.net>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Jeff King 2017-03-02 03:21:27 -05:00 committed by Junio C Hamano
parent e322b60d65
commit 311fc74826
2 changed files with 2 additions and 5 deletions

View File

@ -1279,17 +1279,14 @@ int interpret_branch_name(const char *name, int namelen, struct strbuf *buf)
return -1;
}
int strbuf_branchname(struct strbuf *sb, const char *name)
void strbuf_branchname(struct strbuf *sb, const char *name)
{
int len = strlen(name);
int used = interpret_branch_name(name, len, sb);
if (used == len)
return 0;
if (used < 0)
used = 0;
strbuf_add(sb, name + used, len - used);
return len;
}
int strbuf_check_branch_ref(struct strbuf *sb, const char *name)

View File

@ -562,7 +562,7 @@ static inline void strbuf_complete_line(struct strbuf *sb)
strbuf_complete(sb, '\n');
}
extern int strbuf_branchname(struct strbuf *sb, const char *name);
extern void strbuf_branchname(struct strbuf *sb, const char *name);
extern int strbuf_check_branch_ref(struct strbuf *sb, const char *name);
extern void strbuf_addstr_urlencode(struct strbuf *, const char *,