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filter-branch: return 2 when nothing to rewrite 

Using the --state-branch option allows us to perform incremental filtering.
This may lead to having nothing to rewrite in subsequent filtering, so we need
a way to recognize this case.
So, let's exit with 2 instead of 1 when this "error" occurs.

Signed-off-by: Michele Locati <michele@locati.it>
Signed-off-by: Junio C Hamano <gitster@pobox.com>
This commit is contained in:
Michele Locati 2018-03-15 18:09:18 +01:00 committed by Junio C Hamano
parent 38e79b1fda
commit 0a0eb2e585
2 changed files with 9 additions and 1 deletions
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8
Documentation/git-filter-branch.txt
View File

@ -222,6 +222,14 @@ this purpose, they are instead rewritten to point at the nearest ancestor that
was not excluded.
EXIT STATUS
-----------
On success, the exit status is `0`. If the filter can't find any commits to
rewrite, the exit status is `2`. On any other error, the exit status may be
any other non-zero value.
Examples
--------

2
git-filter-branch.sh
View File

@ -310,7 +310,7 @@ git rev-list --reverse --topo-order --default HEAD \
die "Could not get the commits"
commits=$(wc -l <../revs | tr -d " ")
test $commits -eq 0 && die "Found nothing to rewrite"
test $commits -eq 0 && die_with_status 2 "Found nothing to rewrite"
# Rewrite the commits
report_progress ()